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Question
Solve the following:
1 – (x – 2) – [(x – 3) – (x – 1)] = 0
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Solution
Given, 1 – (x – 2) – [(x – 3) – (x – 1)] = 0
⇒ 1 – x + 2 – [x – 3 – x + 1] = 0
⇒ 3 – x – [– 2] = 0
⇒ 3 – x + 2 = 0
⇒ – x + 5 = 0
⇒ – x = – 5 ...[Transposing 5 to RHS]
⇒ `(-x)/(-1) = (-5)/(-1)` ...[Dividing both sides by –1]
∴ x = 5
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