Advertisements
Advertisements
Question
Solve the following quadratic equation using formula method only
`2x^2 - 2 . sqrt 6x + 3 = 0`
Advertisements
Solution
`2x^2 - 2 . sqrt 6x + 3 = 0`
a = 2 ; b = `-2 sqrt 6` ; c =3
D = `"b"^2 - 4 "ac"`
`= (- 2 sqrt 6)^2 - 4(2)(3)`
= 24 - 24
= 0
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(-(- 2 sqrt 6) +- 0)/(2 xx 2)`
x = `sqrt 6/2`
APPEARS IN
RELATED QUESTIONS
Solve for x using the quadratic formula. Write your answer corrected to two significant figures. (x - 1)2 - 3x + 4 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(4 - k)x2 + (2k + 4)x + 8k + 1 = 0
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 2x + 1 = 0
Find the value of the discriminant in the following quadratic equation:
x2 +2x-2=0
Solve the following quadratic equation using formula method only
`"x"^2 + 1/2 "x" = 3`
`10x -(1)/x` = 3
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
(k + 1)x2 + (2k + 1)x - 9 = 0, k + 1 ≠ 0.
Find the value(s) of k for which each of the following quadratic equation has equal roots: 3kx2 = 4(kx – 1)
If the roots of ax2 + bx + c = 0 are in the ratio m : n, then:
If one root of the quadratic equation 2x2 + kx – 6 = 0 is 2, the value of k is:
