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प्रश्न
Solve the following quadratic equation using formula method only
`2x^2 - 2 . sqrt 6x + 3 = 0`
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उत्तर
`2x^2 - 2 . sqrt 6x + 3 = 0`
a = 2 ; b = `-2 sqrt 6` ; c =3
D = `"b"^2 - 4 "ac"`
`= (- 2 sqrt 6)^2 - 4(2)(3)`
= 24 - 24
= 0
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(-(- 2 sqrt 6) +- 0)/(2 xx 2)`
x = `sqrt 6/2`
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