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Question
If one root of equation (p – 3) x2 + x + p = 0 is 2, the value of p is ______.
Options
– 2
2
± 2
1 and 2
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Solution
If one root of equation (p – 3) x2 + x + p = 0 is 2, the value of p is 2.
Explanation:
Given equation be
(p – 3) x2 + x + p = 0 ...(1)
Since x = 2 is one root of equation (1)
∴ 2 satisfies the given equation (i).
`\implies` (p – 3) · 22 + 2 + p = 0
`\implies` 4(p – 3) + 2 + p = 0
`\implies` 4p – 12 + 2 + p = 0
`\implies` 5p – 10 = 0
`\implies` 5p = 10
`\implies` p = 2
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