Advertisements
Advertisements
Question
ax2 + (4a2 - 3b)x - 12 ab = 0
Advertisements
Solution
ax2 + (4a2 - 3b)x - 12 ab = 0
⇒ ax2 + 4a2x - 3bx - 12ab = 0
⇒ ax (x + 4a) - 3b(x + 4a) = 0
⇒ (ax - 3b) (x + 4a) = 0
⇒ x = `(3b)/a or -4a` are two roots of equation.
RELATED QUESTIONS
Solve for x : ` 2x^2+6sqrt3x-60=0`
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 6x + 1 = 0
Find the value of the discriminant in the following quadratic equation:
2x2 - 5x + 3 = 0
Write the discriminant of the quadratic equation (x + 5)2 = 2 (5x − 3).
Find the values of m so that the quadratic equation 3x2 – 5x – 2m = 0 has two distinct real roots.
The roots of the quadratic equation `"x" + 1/"x" = 3`, x ≠ 0 are:
If one root of the quadratic equation 2x2 + kx – 6 = 0 is 2, the value of k is:
Solve for x: `5/2 x^2 + 2/5 = 1 - 2x`.
Find the discriminant of the quadratic equation `3x^2 - 2x + 1/3` = 0 and hence find the nature of its roots.
Solve the following quadratic equation:
x2 + 4x – 8 = 0
Give your Solution correct to one decimal place.
(Use mathematical tables if necessary.)
