Advertisements
Advertisements
Question
ax2 + (4a2 - 3b)x - 12 ab = 0
Advertisements
Solution
ax2 + (4a2 - 3b)x - 12 ab = 0
⇒ ax2 + 4a2x - 3bx - 12ab = 0
⇒ ax (x + 4a) - 3b(x + 4a) = 0
⇒ (ax - 3b) (x + 4a) = 0
⇒ x = `(3b)/a or -4a` are two roots of equation.
RELATED QUESTIONS
Write the value of k for which the quadratic equation x2 − kx + 4 = 0 has equal roots.
Solve the following quadratic equation using formula method only
x2 - 4x - 1 = 0
Solve the following quadratic equation using formula method only
5x2 - 19x + 17 = 0
Solve the following quadratic equation using formula method only
`sqrt 3 "x"^2 + 10 "x" - 8 sqrt 3 = 0`
(3x - 5)(2x + 7) = 0
Solve the following by reducing them to quadratic equations:
x4 - 26x2 + 25 = 0
If the coefficient of x2 and the constant term have the same sign and if the coefficient of x term is zero, then the quadratic equation has no real roots.
Find the roots of the quadratic equation by using the quadratic formula in the following:
`1/2x^2 - sqrt(11)x + 1 = 0`
Find the value of 𝑚 so that the quadratic equation 𝑚𝑥(5𝑥 − 6) = 0 has two equal roots.
If α and β be the roots of the equation x2 – 2x + 2 = 0, then the least value of n for which `(α/β)^n` = 1 is ______.
