Advertisements
Advertisements
प्रश्न
ax2 + (4a2 - 3b)x - 12 ab = 0
Advertisements
उत्तर
ax2 + (4a2 - 3b)x - 12 ab = 0
⇒ ax2 + 4a2x - 3bx - 12ab = 0
⇒ ax (x + 4a) - 3b(x + 4a) = 0
⇒ (ax - 3b) (x + 4a) = 0
⇒ x = `(3b)/a or -4a` are two roots of equation.
संबंधित प्रश्न
Find that non-zero value of k, for which the quadratic equation kx2 + 1 − 2(k − 1)x + x2 = 0 has equal roots. Hence find the roots of the equation.
Solve the following equation:
`x - 18/x = 6` Give your answer correct to two significant figures.
Determine the nature of the roots of the following quadratic equation :
2x2 + 5x - 6 = 0
If x = 2 and x = 3 are roots of the equation 3x² – 2kx + 2m = 0. Find the values of k and m.
Form the quadratic equation whose roots are:
`sqrt(3) and 3sqrt(3)`
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 5x + 7 = 0
In each of the following, determine whether the given numbers are roots of the given equations or not; x2 – 5x + 6 = 0; 2, – 3
Discuss the nature of the roots of the following quadratic equations : `x^2 - (1)/(2)x + 4` = 0
The quadratic equation `2x^2 - sqrt(5)x + 1 = 0` has ______.
If 4 is a root of equation x2 + kx – 4 = 0; the value of k is ______.
