Advertisements
Advertisements
प्रश्न
ax2 + (4a2 - 3b)x - 12 ab = 0
Advertisements
उत्तर
ax2 + (4a2 - 3b)x - 12 ab = 0
⇒ ax2 + 4a2x - 3bx - 12ab = 0
⇒ ax (x + 4a) - 3b(x + 4a) = 0
⇒ (ax - 3b) (x + 4a) = 0
⇒ x = `(3b)/a or -4a` are two roots of equation.
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
(4 - k)x2 + (2k + 4)x + 8k + 1 = 0
The equation `3x^2 – 12x + (n – 5) = 0` has equal roots. Find the value of n.
Solve the following quadratic equation using formula method only
x2 - 4x - 1 = 0
If the root of the given quadratic equation are real and equal, then find the value of ‘k’ X2 + 2X + k = 0.
α and β are the roots of 4x2 + 3x + 7 = 0, then the value of `1/α + 1/β` is:
Which of the following equations has the sum of its roots as 3?
(x2 + 1)2 – x2 = 0 has ______.
Every quadratic equation has at least two roots.
The probability of selecting integers a ∈ [–5, 30] such that x2 + 2(a + 4)x – 5a + 64 > 0, for all x ∈ R, is ______.
The roots of equation (q – r)x2 + (r – p)x + (p – q) = 0 are equal.
Prove that 2q = p + r; i.e., p, q, and r are in A.P.
