Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
2x2 + x-1=0
Advertisements
उत्तर
2x2 + x-1=0
b2 - 4ac
= (1)2-4(2)(-1)
= 1+ 8
=9
Since 9 is a perfect square and greater than 0, hence the roots are real and rational.
APPEARS IN
संबंधित प्रश्न
Solve the equation by using the formula method. 3y2 +7y + 4 = 0
Prove that both the roots of the equation (x – a)(x – b) + (x – b)(x – c) + (x – c)(x – a) = 0 are real but they are equal only when a = b = c.
Determine the nature of the roots of the following quadratic equation :
x2 +3x+1=0
Determine the nature of the roots of the following quadratic equation :
4x2 - 8x + 5 = 0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
x2 + 4x + 5 = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
9a2b2x2 - 48abc + 64c2d2 = 0, a ≠ 0, b ≠ 0
If `sqrt(2)` is a root of the equation `"k"x^2 + sqrt(2x) - 4` = 0, find the value of k.
Every quadratic equation has at least one real root.
Every quadratic equation has at least two roots.
Find the value(s) of 'a' for which the quadratic equation x2 – ax + 1 = 0 has real and equal roots.
