Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
2x2 + x-1=0
Advertisements
उत्तर
2x2 + x-1=0
b2 - 4ac
= (1)2-4(2)(-1)
= 1+ 8
=9
Since 9 is a perfect square and greater than 0, hence the roots are real and rational.
APPEARS IN
संबंधित प्रश्न
Without solving, examine the nature of roots of the equation 2x2 – 7x + 3 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + 3x + k = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx - 4 = 0
Solve the following by reducing them to quadratic equations:
x4 - 26x2 + 25 = 0
The roots of the quadratic equation 6x2 – x – 2 = 0 are:
The sum of the roots of the quadratic equation 3x2 – 9x + 5 = 0 is:
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
The value of k for which the equation x2 + 2(k + 1)x + k2 = 0 has equal roots is:
A natural number, when increased by 12, equals 160 times its reciprocal. Find the number.
Find the value of ‘p’ for which the quadratic equation px(x – 2) + 6 = 0 has two equal real roots.
