Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
x2 -4x + 4=0
Advertisements
उत्तर
x2 -4x + 4=0
b2 - 4ac
= (-4)2- 4(1)(4)
= 16- 16
=0
Since discriminant is 01 hence the roots are real and equal .
APPEARS IN
संबंधित प्रश्न
Without solving, examine the nature of roots of the equation 2x2 + 2x + 3 = 0
Find the values of k for the following quadratic equation, so that they have two equal roots.
kx (x - 2) + 6 = 0
Determine the nature of the roots of the following quadratic equation:
`3/5x^2-2/3x+1=0`
Find the values of k for which the roots are real and equal in each of the following equation:
(3k+1)x2 + 2(k + 1)x + k = 0
If one root of the quadratic equation ax2 + bx + c = 0 is double the other, prove that 2b2 = 9 ac.
If the roots of ax2 + bx + c = 0 are in the ratio m : n, then:
(x2 + 1)2 – x2 = 0 has:
If b and c are odd integers, then the equation x2 + bx + c = 0 has ______.
Assertion (A): If one root of the quadratic equation 4x2 – 10x + (k – 4) = 0 is reciprocal of the other, then value of k is 8.
Reason (R): Roots of the quadratic equation x2 – x + 1 = 0 are real.
One root of equation 3x2 – mx + 4 = 0 is 1, the value of m is ______.
