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Shabnam takes 20 minutes to reach her school if she goes at a speed of 6 km/h. If she wants to reach school in 24 minutes, what should be her speed?

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Question

Shabnam takes 20 minutes to reach her school if she goes at a speed of 6 km/h. If she wants to reach school in 24 minutes, what should be her speed?

Sum
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Solution

Shabnam’s speed = 6 km/h = `(6 xx 1000)/60` m/min

∴ Total distance covered by Shabnam in 20 min = `(6 xx 1000)/60 xx 20`  ...[∵ Distance = Speed × Time]

= `1000/10 xx 20`

= 100 × 20   

= 2000 m

If she want to reach the school in 24 min, then she should maintain the speed = `2000/24`

= `1000/12`

= `500/6` m/min

= `(500 xx 60)/(1000 xx 6)`    ...`[∵ 1km = 1/1000 and 1h = 60 min]`

= 5 km/h

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Chapter 10: Direct and Inverse Proportions - Exercise [Page 326]

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NCERT Exemplar Mathematics Exemplar [English] Class 8
Chapter 10 Direct and Inverse Proportions
Exercise | Q 89. | Page 326

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