Advertisements
Advertisements
Question
Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in the following figure is ______.

Options
2 : 1 : 3
1 : 3 : 2
2 : 3 : 1
1 : 2 : 3
Advertisements
Solution
Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in the following figure is 2 : 1 : 3.
Explanation:

We know that, area of triangle = `1/2` × base × height
So, area of triangle MNO = `1/2` × NO × MO
= `1/2` × 5 × 4
= `1/2` × 20
= 10 cm2
Area of triangle MOP = `1/2` × MO × OP
= `1/2` × 5 × 2
= `1/2` × 10
= 5 cm2
Area of triangle MPQ = `1/2` × MO × PQ ...[MP = MO]
= `1/2` × 5 × 6
= `1/2` × 30
= 15 cm2
So, the ratio of area = 10 : 5 : 15 ...[Divide each by 5]
Then we get, 2 : 1 : 3
APPEARS IN
RELATED QUESTIONS
Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
Find the area of a triangle whose vertices are
(6,3), (-3,5) and (4,2)
Prove that the points (a, b), (a1, b1) and (a −a1, b −b1) are collinear if ab1 = a1b.
Two vertices of a triangle are (1, 2), (3, 5) and its centroid is at the origin. Find the coordinates of the third vertex.
Prove analytically that the line segment joining the middle points of two sides of a triangle is equal to half of the third side.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
Find the value of p for which the points (−5, 1), (1, p) and (4, −2) are collinear.
Find the area of the following triangle:

A field is in the shape of a right angled triangle whose base is 25 m and height 20 m. Find the cost of levelling the field at the rate of ₹ 45 per sq.m2
Find the area of the triangle whose vertices are (–8, 4), (–6, 6) and (–3, 9).
