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Prove that the function f given by f(x) = log sin x is strictly increasing on (0,π2) and strictly decreasing on (π2,π) - Mathematics

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Question

Prove that the function f given by f(x) = log sin x is strictly increasing on `(0, pi/2)` and strictly decreasing on `(pi/2, pi)`

Sum
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Solution

We have, f (x) = log (sin x)

Differentiating w.r.t x, we get

`f' (x) = 1/ (sin x) (cos x) = cot x`

As cot x >0 for all `x in (0, pi/2)` and cot x < 0

For all `x in (pi/2, pi),` Therefore, f (x) is strictly increasing on `(0, pi/2)` and strictly decreasing on `(pi/2, pi).`

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Chapter 6: Application of Derivatives - Exercise 6.2 [Page 206]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 6 Application of Derivatives
Exercise 6.2 | Q 16 | Page 206

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