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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Prove that abbcca[a→-b→,b→-c→,c→-a→] = 0 - Mathematics

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Question

Prove that `[vec"a" - vec"b", vec"b" - vec"c", vec"c" - vec"a"]` = 0

Sum
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Solution

`[vec"a" - vec"b", vec"b" - vec"c", vec"c" - vec"a"] = (vec"a" - vec"b")*[(vec"b" - vec"c") xx (vec"c" - vec"a")]`

= `(vec"a" - vec"b")*[vec"b" xx vec"c" - vec"b" xx vec"a" - vec"c" xx vec"c" + vec"c" xx vec"a"]`

= `vec"a"*(vec"b" xx vec"c") - vec"a"*(vec"b" xx vec"a") - vec"a"*(vec"c" xx vec"c") + vec"a"*(vec"c" xx vec"a") - vec"b"*(vec"b" xx vec"c") + vec"b"*(vec"b" xx vec"a") + vec"b"*(vec"c" xx vec"c") - vec"b"*(vec"c" xx vec"a")`

= `vec"a"*(vec"b" xx vec"c") - 0 - 0 + 0 - 0 + 0 + 0 - vec"b"*(vec"c" xx vec"a")`

= `[vec"a", vec"b", vec"c"] - [vec"a", vec"b", vec"c"]` = 0

Hence proved.

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Vector Triple Product
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Chapter 6: Applications of Vector Algebra - Exercise 6.3 [Page 242]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 6 Applications of Vector Algebra
Exercise 6.3 | Q 3 | Page 242

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