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Question
Out of 750 families with 4 children each, how many families would be expected to have children of both sexes? Assume equal probabilities for boys and girls.
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Solution
Assume equal probabilities for boys and girls
Let p be the probability of having a boy
Let x be the random variable for getting either a boy or a girl
∴ p = `1/2` and q = `1/2` and n = 4
In binomial distribution P(X = 4) = ncxpxqn-x
Here the binomial distribution is P(X= x) = `4"C"_x (1/2)^x (1/2)^("n" - x)`
P(children of both sexes) = P(X = 1) + P(X = 2) + P(X = 3)
= `4"C"_1 (1/2)^1 (1/2)^(4 - 2) + 4"C"_2 (1/2)^2 (1/2)^(4 - 2) + 4"C"_3 (1/2)^3 (1/2)^(4 - 3)`
= `4 xx (1/16) + 6 xx (1/16) + 4 xx 1/16`
= `1/16[4 + 6 + 4]`
= `14/16`
= 0.875 x 750
For 750 families P(X = 2) = 0.875 × 750
= 656.25
= 656 ......(approximately)
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