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Question
X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(X < 40)
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Solution
Given X ~ N(µ, σ2)
µ = 30
σ = 4
P(X < 40) = `"P"("Z" < (40 -30)/4)`
= P(Z < 2.5)
= 0.5 + P(0 < Z < 2.5)
= 0.5 + 0.4938
= 0.9938
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