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Question
Observe the given figure and state the three pairs of equal parts in triangles ABC and DBC.
- Is ∆ABC ≅ ∆DCB? Why?
- Is AB = DC? Why?
- Is AC = DB? Why?
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Solution
i. In ∆ABC and ∆DCB,
∠ABC = ∠DCB = 40° + 30 = 70° ...(Given)
∠ACB = ∠DBC = 30° ...(Given)
BC = CB ...(Common)
∴ ∆ABC ≅ ∆DCB ...(ASA criterion)
ii. Yes, by using part (i), we get
AB = DC ...(By C.P.C.T.)
iii. Yes, by using (i) part, we get
AC = DB ...(By C.P.C.T.)
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