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In the following figure, QS ⊥ PR, RT ⊥ PQ and QS = RT. Is ∆QSR = ∆RTO? Give reasons. Is ∠PQR = ∠PRQ? Give reasons. - Mathematics

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Question

In the following figure, QS ⊥ PR, RT ⊥ PQ and QS = RT.

  1. Is ∆QSR = ∆RTO? Give reasons.
  2. Is ∠PQR = ∠PRQ? Give reasons.

Give Reasons
Sum
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Solution

i. In ∆QSR and ∆RTQ,

∠QSR = ∠RTQ = 90°  ...(∵ QS ⊥ PR and RT ⊥ PQ (given))

QS = RT  ...(Given)

QR = RQ  ...(Common hypotenuse)

∴ ∆QSR ≅ ∆RTQ  ...(RHS criterion)

ii. Yes, by using (i) part, we get

∠TQR = ∠SRQ  ...(By C.P.C.T)

⇒ ∠PQR = PRQ

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Chapter 6: Triangles - Exercise [Page 184]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 6 Triangles
Exercise | Q 154. | Page 184

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