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Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His ______ is ______ %. - Mathematics

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Question

Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His ______ is ______ %.

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Solution

Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His profit is 10 %.

Explanation:

From the question, it is given that, cost price of one orange = ₹ 4

Cost price of 120 oranges = ₹ 4 × 120 = ₹ 480

So, selling price of 60% of oranges = ₹ 5 per each

60% of 120 oranges = `60/100 xx 120`

= `7200/100`

= 72 oranges

Selling price of 72 oranges = 72 × 5 = ₹ 360

SP of remaining oranges = 120 – 72 × 3.50

= 48 × 3.50

= ₹ 168

Therefore total selling price of 120 oranges = ₹ 360 + ₹ 168

= ₹ 528

SP is more than CP so, Profit = SP – CP

= 528 – 480

= ₹ 48

We know that, Profit percentage = `"Profit"/"CP" xx 100`

= `48/480 xx 100`

= 10%

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Chapter 7: Comparing Quantities - Exercise [Page 201]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 7 Comparing Quantities
Exercise | Q 45. | Page 201

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