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प्रश्न
Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His ______ is ______ %.
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उत्तर
Narain bought 120 oranges at ₹ 4 each. He sold 60 % of the oranges at ₹ 5 each and the remaining at ₹ 3.50 each. His profit is 10 %.
Explanation:
From the question, it is given that, cost price of one orange = ₹ 4
Cost price of 120 oranges = ₹ 4 × 120 = ₹ 480
So, selling price of 60% of oranges = ₹ 5 per each
60% of 120 oranges = `60/100 xx 120`
= `7200/100`
= 72 oranges
Selling price of 72 oranges = 72 × 5 = ₹ 360
SP of remaining oranges = 120 – 72 × 3.50
= 48 × 3.50
= ₹ 168
Therefore total selling price of 120 oranges = ₹ 360 + ₹ 168
= ₹ 528
SP is more than CP so, Profit = SP – CP
= 528 – 480
= ₹ 48
We know that, Profit percentage = `"Profit"/"CP" xx 100`
= `48/480 xx 100`
= 10%
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M.P. in ₹ |
S.P. in ₹ |
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Profit in ₹ |
Loss in ₹ |
| (i) | 110 | 130 | Nil | |||
| (ii) | 110 | 130 | 10 | |||
| (iii) | 110 | 130 | 30 | |||
| (iv) | 110 | 120 | Nil | 10 | ||
| (v) | 120 | 10 | 20 | Nil |
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| (i) 3:5 | (A) ₹ 54 |
| (ii) 2.5 | (B) ₹ 47 |
| (iii) 100% | (C) ₹ 53 |
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| (N) ₹ 164 | |
| (O) 3 : 3 |
