Advertisements
Advertisements
Question
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
Sum
Advertisements
Solution
`(2"a"^3-3"a"^2"b")(-1/2"ab"^2)`
= `-1/2"ab"^2 (2"a"^3-3"a"^2"b")`
= `2"a"^3xx-1/2"ab"^2-3"a"^2"b"xx-1/2"ab"^2`
= `-"a"^4"b"^2+3/2"a"^3"b"^3`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
4, 7p
Find the product of the following pair of monomial.
4p3, − 3p
Obtain the product of a, − a2, a3
Multiply: x2+ x + 1 by 1 − x
Multiply: 2m2 − 3m − 1 and 4m2 − m − 1
Multiply: a2, ab and b2
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
abc + bca + cab is a monomial.
Multiply the following:
15xy2, 17yz2
Multiply the following:
abc, (bc + ca)
