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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Multiply (4x2 + 9) and (3x – 2) - Mathematics

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Question

Multiply (4x2 + 9) and (3x – 2)

Sum
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Solution

(4x2 + 9)(3x – 2) = 4x2(3x – 2) + 9(3x – 2)

= (4x2)(3x) – (4x2)(2) + 9(3x) – 9(2)

= (4 × 3 × x × x2) – (4 × 2 × x2) + (9 × 3 × x) – 18

= 12x3 – 8x2 + 27x – 18(4x3 + 9)(3x – 2)

= 12x3 – 8x2 + 27x – 18

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Chapter 3: Algebra - Exercise 3.5 [Page 97]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 3 Algebra
Exercise 3.5 | Q 2 | Page 97
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