Advertisements
Advertisements
प्रश्न
Multiply (4x2 + 9) and (3x – 2)
Advertisements
उत्तर
(4x2 + 9)(3x – 2) = 4x2(3x – 2) + 9(3x – 2)
= (4x2)(3x) – (4x2)(2) + 9(3x) – 9(2)
= (4 × 3 × x × x2) – (4 × 2 × x2) + (9 × 3 × x) – 18
= 12x3 – 8x2 + 27x – 18(4x3 + 9)(3x – 2)
= 12x3 – 8x2 + 27x – 18
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4, 7p
Find the product of the following pair of monomial.
4p, 0
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
(−xy3) × (yx3) × (xy)
Multiply: 5a − 1 by 7a − 3
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
A total of 90 currency notes, consisting only of ₹ 5 and ₹ 10 denominations, amount to ₹ 500. Find the number of notes in each denomination.
Three consecutive integers, when taken in increasing order and multiplied by 2, 3 and 4 respectively, total up to 74. Find the three numbers.
Multiply the following:
–7pq2r3, –13p3q2r
Multiply the following:
x2y2z2, (xy – yz + zx)
