Advertisements
Advertisements
प्रश्न
Multiply (4x2 + 9) and (3x – 2)
Advertisements
उत्तर
(4x2 + 9)(3x – 2) = 4x2(3x – 2) + 9(3x – 2)
= (4x2)(3x) – (4x2)(2) + 9(3x) – 9(2)
= (4 × 3 × x × x2) – (4 × 2 × x2) + (9 × 3 × x) – 18
= 12x3 – 8x2 + 27x – 18(4x3 + 9)(3x – 2)
= 12x3 – 8x2 + 27x – 18
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4, 7p
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( \frac{1}{8} x^2 y^4 \right) \times \left( \frac{1}{4} x^4 y^2 \right) \times \left( xy \right) \times 5\]
Multiply: 5a − 1 by 7a − 3
Multiply: x2+ x + 1 by 1 − x
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
Solve: (-12x) × 3y2
Multiply the following:
abc, (bc + ca)
Multiply the following:
(p + 6), (q – 7)
