Advertisements
Advertisements
प्रश्न
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
योग
Advertisements
उत्तर
`(2"a"^3-3"a"^2"b")(-1/2"ab"^2)`
= `-1/2"ab"^2 (2"a"^3-3"a"^2"b")`
= `2"a"^3xx-1/2"ab"^2-3"a"^2"b"xx-1/2"ab"^2`
= `-"a"^4"b"^2+3/2"a"^3"b"^3`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
− 4p, 7p
Obtain the product of 2, 4y, 8y2, 16y3
Obtain the product of a, 2b, 3c, 6abc.
Multiply: `2/3"ab"` by `-1/4 "a"^2"b"`
Multiply (4x2 + 9) and (3x – 2)
Product of the following monomials 4p, –7q3, –7pq is ______.
abc + bca + cab is a monomial.
Multiply the following:
15xy2, 17yz2
Multiply the following:
7pqr, (p – q + r)
Multiply the following:
6mn, 0mn
