Advertisements
Advertisements
प्रश्न
Multiply the following:
3x2y2z2, 17xyz
Advertisements
उत्तर
We have,
3x2y2z2 and 17xyz
∴ 3x2y2z2 × 17xyz = (3 × 17)x2y2z2 × xyz
= 51x3y3z3
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
− 4p, 7pq
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
\[\left( \frac{4}{9}ab c^3 \right) \times \left( - \frac{27}{5} a^3 b^2 \right) \times \left( - 8 b^3 c \right)\]
Multiply: −5cd2 by − 5cd2
Multiply: 4a and 6a + 7
Multiply: x + 4 by x − 5
Multiply: 2m2 − 3m − 1 and 4m2 − m − 1
Multiply: abx, −3a2x and 7b2x3
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
(p + 6), (q – 7)
