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प्रश्न
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
योग
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उत्तर
| Length | Breadth | Area |
| p | q | pq |
| 10m | 5n | 10m × 5n = 50mn |
| 20x2 | 5y2 | 20x2 × 5y2 = 100x2y2 |
| 4x | 3x2 | 4x × 3x2 = 12x3 |
| 3mn | 4np | 3mn × 4np = 12mn2p |
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Obtain the product of a, − a2, a3
Multiply : 8ab2 by − 4a3b4
Multiply: x2+ x + 1 by 1 − x
Multiply: a2, ab and b2
Multiply: abx, −3a2x and 7b2x3
Solve: (-12x) × 3y2
Multiply the following:
–7pq2r3, –13p3q2r
Multiply the following:
x2y2z2, (xy – yz + zx)
