Advertisements
Advertisements
प्रश्न
Multiply the following:
(p + 6), (q – 7)
योग
Advertisements
उत्तर
We have,
(p + 6) and (q – 7)
∴ (p + 6) × (q – 7) = p(q – 7) + 6(q – 7)
= pq – 7p + 6q – 42
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
APPEARS IN
संबंधित प्रश्न
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Obtain the product of xy, yz, zx.
Multiply: 4a and 6a + 7
Multiply: 5a − 1 by 7a − 3
Multiply: abx, −3a2x and 7b2x3
Multiply (4x2 + 9) and (3x – 2)
Area of a rectangle with length 4ab and breadth 6b2 is ______.
Multiply the following:
–5a2bc, 11ab, 13abc2
Multiply the following:
7pqr, (p – q + r)
