Advertisements
Advertisements
प्रश्न
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Advertisements
उत्तर
We know that.
Volume = Length × Breadth × Height
Volume = 5a × 3a2 × 7a4
= 5 × 3 × 7 × a × a2 × a4
= 105a7
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
− 4p, 7pq
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( - \frac{4}{7} a^2 b \right) \times \left( - \frac{2}{3} b^2 c \right) \times \left( - \frac{7}{6} c^2 a \right)\]
Multiply : 8ab2 by − 4a3b4
Multiply: 12a + 5b by 7a − b
Multiply: 2m2 − 3m − 1 and 4m2 − m − 1
Multiply: a2, ab and b2
Multiply: `2"x"+1/2"y"` and `2"x"-1/2"y"`
Solve: (-12x) × 3y2
abc + bca + cab is a monomial.
