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प्रश्न
Find the product of the following pair of monomial.
− 4p, 7pq
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उत्तर
The product will be as follows:
− 4p × 7pq
= − 4 × p × 7 × p × q
= (− 4 × 7) × (p × p × q)
= − 28p2q
संबंधित प्रश्न
Express each of the following product as a monomials and verify the result for x = 1, y = 2: \[\left( - \frac{4}{7} a^2 b \right) \times \left( - \frac{2}{3} b^2 c \right) \times \left( - \frac{7}{6} c^2 a \right)\]
Multiply : 8ab2 by − 4a3b4
Multiply: x + 4 by x − 5
Multiply: 12a + 5b by 7a − b
Multiply: a2, ab and b2
Multiply: `-2/3"a"^7"b"^2` and `-9/4"a""b"^5`
Multiply: `2"a"^3-3"a"^2"b"` and `-1/2"ab"^2`
Multiply: `2"x"+1/2"y"` and `2"x"-1/2"y"`
Three consecutive integers, when taken in increasing order and multiplied by 2, 3 and 4 respectively, total up to 74. Find the three numbers.
Multiply the following:
–3x2y, (5y – xy)
