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Question
Find the product of the following pair of monomial.
− 4p, 7pq
Sum
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Solution
The product will be as follows:
− 4p × 7pq
= − 4 × p × 7 × p × q
= (− 4 × 7) × (p × p × q)
= − 28p2q
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RELATED QUESTIONS
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
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