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Question
Multiply the following:
–5a2bc, 11ab, 13abc2
Sum
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Solution
We have,
–5a2bc, 11ab and 13abc2
∴ –5a2bc × 11ab × 13abc2 = (–5 × 11 × 13)a2bc × ab × abc2
= –715a4b3c3
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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 230]
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