Advertisements
Advertisements
Question
Product of the following monomials 4p, –7q3, –7pq is ______.
Options
196 p2q4
196 pq4
– 196 p2q4
196 p2q3
Advertisements
Solution
Product of the following monomials 4p, –7q3, –7pq is 196 p2q4.
Explanation:
Required product = 4p × (–7q3) × (–7pq)
= 4 × (–7) × (–7)p × q3 × pq ...[Multiplying the numerical coefficients]
= 196 p2q4 ...[Multiplying the literal factors having same variables]
APPEARS IN
RELATED QUESTIONS
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
Multiply: 4a and 6a + 7
Multiply: 5a − 1 by 7a − 3
Multiply: `2"x"+1/2"y"` and `2"x"-1/2"y"`
| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
The length of a rectangle is `1/3` of its breadth. If its perimeter is 64 m, then find the length and breadth of the rectangle.
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Multiply the following:
15xy2, 17yz2
Multiply the following:
(p + 6), (q – 7)
Multiply the following:
6mn, 0mn
