Advertisements
Advertisements
Question
Product of the following monomials 4p, –7q3, –7pq is ______.
Options
196 p2q4
196 pq4
– 196 p2q4
196 p2q3
Advertisements
Solution
Product of the following monomials 4p, –7q3, –7pq is 196 p2q4.
Explanation:
Required product = 4p × (–7q3) × (–7pq)
= 4 × (–7) × (–7)p × q3 × pq ...[Multiplying the numerical coefficients]
= 196 p2q4 ...[Multiplying the literal factors having same variables]
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
4, 7p
Multiply: 4a and 6a + 7
Multiply: −8x and 4 − 2x − x2
Multiply: 2a2 − 5a − 4 and −3a
Multiply: `-3/2"x"^5"y"^3` and `4/9"a"^2"x"3"y"`
Multiply: `-2/3"a"^7"b"^2` and `-9/4"a""b"^5`
Solve: ( -3x2 ) × ( -4xy)
A total of 90 currency notes, consisting only of ₹ 5 and ₹ 10 denominations, amount to ₹ 500. Find the number of notes in each denomination.
Multiply the following:
–7pq2r3, –13p3q2r
Multiply the following:
3x2y2z2, 17xyz
