Advertisements
Advertisements
Question
Area of a rectangle with length 4ab and breadth 6b2 is ______.
Options
24a2b2
24ab3
24ab2
24ab
Advertisements
Solution
Area of a rectangle with length 4ab and breadth 6b2 is 24ab3.
Explanation:
We know that, area of a rectangle = Length × Breadth = 4ab × 6b2
This is the product of two monomials.
∴ Area of rectangle = (4 × 6)ab × b2
= 24ab3
APPEARS IN
RELATED QUESTIONS
Find the product of the following pair of monomial.
− 4p, 7pq
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
2p, 4q, 8r
Obtain the product of a, − a2, a3
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
\[\left( \frac{4}{9}ab c^3 \right) \times \left( - \frac{27}{5} a^3 b^2 \right) \times \left( - 8 b^3 c \right)\]
Multiply: 4a and 6a + 7
Multiply: `-3/2"x"^5"y"^3` and `4/9"a"^2"x"3"y"`
| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
Solve: (-12x) × 3y2
Multiply the following:
3x2y2z2, 17xyz
