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प्रश्न
Area of a rectangle with length 4ab and breadth 6b2 is ______.
पर्याय
24a2b2
24ab3
24ab2
24ab
MCQ
रिकाम्या जागा भरा
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उत्तर
Area of a rectangle with length 4ab and breadth 6b2 is 24ab3.
Explanation:
We know that, area of a rectangle = Length × Breadth = 4ab × 6b2
This is the product of two monomials.
∴ Area of rectangle = (4 × 6)ab × b2
= 24ab3
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संबंधित प्रश्न
Find the product of the following pair of monomial.
− 4p, 7pq
Find the product of the following pair of monomial.
4p3, − 3p
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the product of a, − a2, a3
Multiply: −5cd2 by − 5cd2
Multiply: 4a and 6a + 7
Multiply: −8x and 4 − 2x − x2
Multiply: abx, −3a2x and 7b2x3
Multiply the following:
3x2y2z2, 17xyz
Multiply the following:
–3x2y, (5y – xy)
