Advertisements
Advertisements
प्रश्न
Area of a rectangle with length 4ab and breadth 6b2 is ______.
पर्याय
24a2b2
24ab3
24ab2
24ab
Advertisements
उत्तर
Area of a rectangle with length 4ab and breadth 6b2 is 24ab3.
Explanation:
We know that, area of a rectangle = Length × Breadth = 4ab × 6b2
This is the product of two monomials.
∴ Area of rectangle = (4 × 6)ab × b2
= 24ab3
APPEARS IN
संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
5a, 3a2, 7a4
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
2p, 4q, 8r
Obtain the product of a, 2b, 3c, 6abc.
Express each of the following product as a monomials and verify the result for x = 1, y = 2:
\[\left( \frac{4}{9}ab c^3 \right) \times \left( - \frac{27}{5} a^3 b^2 \right) \times \left( - 8 b^3 c \right)\]
Multiply: `2"x"+1/2"y"` and `2"x"-1/2"y"`
Multiply (4x2 + 9) and (3x – 2)
A total of 90 currency notes, consisting only of ₹ 5 and ₹ 10 denominations, amount to ₹ 500. Find the number of notes in each denomination.
Product of the following monomials 4p, –7q3, –7pq is ______.
Multiply the following:
x2y2z2, (xy – yz + zx)
