Advertisements
Advertisements
Question
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is ______.
Options
12a3bc2
12a3bc
12a2bc
2ab + 3ac + 2ac
Advertisements
Solution
Volume of a rectangular box (cuboid) with length = 2ab, breadth = 3ac and height = 2ac is 12a3bc2.
Explanation:
We know that, volume of a cuboid = Length × Breadth × Height
= 2ab × 3ac × 2ac
= (2 × 3 × 2)ab × ac × ac
= 12a × a × a × b × c × c
= 12a3bc2
APPEARS IN
RELATED QUESTIONS
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths, respectively.
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
xy, 2x2y, 2xy2
Obtain the product of xy, yz, zx.
Obtain the product of a, − a2, a3
Multiply : 8ab2 by − 4a3b4
Multiply: x + 4 by x − 5
Multiply: a2, ab and b2
Multiply: `-3/2"x"^5"y"^3` and `4/9"a"^2"x"3"y"`
Multiply: `2"x"+1/2"y"` and `2"x"-1/2"y"`
Area of a rectangle with length 4ab and breadth 6b2 is ______.
