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Question
Magnetic moment of \[\ce{[MnCl4]^{2-}}\] is 5.92 BM. Explain giving reason.
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Solution
The magnetic moment of 5.92 BM corresponds to the presence of five unpaired electrons in the d-orbitals of \[\ce{Mn^2+}\] ion. As a result the hybridisation involved is sp3 rather than dsp2. Thus tetrahedral structure of \[\ce{[MnCl4 ]^{2-}}\] complex will show 5.92 BM magnetic moment value.
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