Question

Let θ = sin^–1 (sin (– 600°), then value of θ is ______.

Options

• `pi/3`

• `pi/2`

• `(2pi)/3`

• `(-2pi)/3`

Answer 1

Let θ = sin^–1 (sin (– 600°), then value of θ is `pi/3`.

Explanation:

`sin^-1 sin(- 600 xx pi/180) = sin^-1 sin((-10pi)/3)`

= `sin^-1 [- sin(4pi - (2pi)/3)]`

= `sin^-1 (sin  (2pi)/3)`

= `sin^-1 (sin(pi - pi/3))`

= `sin^-1(sin  pi/3)`

= `pi/3`.