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The greatest and least values of (sin–1x)2 + (cos–1x)2 are respectively ______. - Mathematics

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Question

The greatest and least values of (sin–1x)2 + (cos–1x)2 are respectively ______.

Options

  • `(5pi^2)/4` and `pi^2/8`

  • `pi/2` and `(-pi)/2`

  • `pi^2/4` ad `(-pi^2)/4`

  • `pi^2/4` and 0

MCQ
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Solution

The greatest and least values of (sin–1x)2 + (cos–1x)2 are respectively `(5pi^2)/4` and `pi^2/8`.

Explanation:

We have (sin–1x)2 + (cos–1x)2

= (sin–1x + cos–1x)2 – 2 sin–1x cos–1x

=  `pi^2/4 - 2sin^1x (pi/2 - sin^-1x)`

= `pi^2/4 - pi sin^-1x + 2(sin^-1x)^2`

= `2[(sin^-1x)^2 - pi/2 sin^-1x + pi^2/8]`

= `2[(sin^-1x - pi/4)^2 + pi^2/16]`

Thus, the least value is `2(pi^2/16)`

i.e. `pi^2/8` and the Greatest value is `2[((-pi)/2 - pi/4)^2 + pi^2/16]`

i.e. `(5pi^2)/4`.

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Chapter 2: Inverse Trigonometric Functions - Solved Examples [Page 31]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Solved Examples | Q 30 | Page 31

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