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प्रश्न
Let θ = sin–1 (sin (– 600°), then value of θ is ______.
विकल्प
`pi/3`
`pi/2`
`(2pi)/3`
`(-2pi)/3`
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उत्तर
Let θ = sin–1 (sin (– 600°), then value of θ is `pi/3`.
Explanation:
`sin^-1 sin(- 600 xx pi/180) = sin^-1 sin((-10pi)/3)`
= `sin^-1 [- sin(4pi - (2pi)/3)]`
= `sin^-1 (sin (2pi)/3)`
= `sin^-1 (sin(pi - pi/3))`
= `sin^-1(sin pi/3)`
= `pi/3`.
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