मराठी

Let θ = sin–1 (sin (– 600°), then value of θ is ______. - Mathematics

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प्रश्न

Let θ = sin–1 (sin (– 600°), then value of θ is ______.

पर्याय

  • `pi/3`

  • `pi/2`

  • `(2pi)/3`

  • `(-2pi)/3`

MCQ
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उत्तर

Let θ = sin–1 (sin (– 600°), then value of θ is `pi/3`.

Explanation:

`sin^-1 sin(- 600 xx pi/180) = sin^-1 sin((-10pi)/3)`

= `sin^-1 [- sin(4pi - (2pi)/3)]`

= `sin^-1 (sin  (2pi)/3)`

= `sin^-1 (sin(pi - pi/3))`

= `sin^-1(sin  pi/3)`

= `pi/3`.

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पाठ 2: Inverse Trigonometric Functions - Solved Examples [पृष्ठ ३१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Solved Examples | Q 31 | पृष्ठ ३१
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