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Let a = [ 1 2 3 − 5 ] and B = [ 1 0 0 2 ] and X Be a Matrix Such that a = Bx, Then X is Equal to - Mathematics

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Question

Let \[A = \begin{bmatrix}1 & 2 \\ 3 & - 5\end{bmatrix}\text{ and }B = \begin{bmatrix}1 & 0 \\ 0 & 2\end{bmatrix}\] and X be a matrix such that A = BX, then X is equal to _____________ .

Options

  • \[\frac{1}{2}\begin{bmatrix}2 & 4 \\ 3 & - 5\end{bmatrix}\]

  • \[\frac{1}{2}\begin{bmatrix}- 2 & 4 \\ 3 & 5\end{bmatrix}\]

  • \[\begin{bmatrix}2 & 4 \\ 3 & - 5\end{bmatrix}\]

  • none of these

MCQ
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Solution

\[\frac{1}{2}\begin{bmatrix}2 & 4 \\ 3 & - 5\end{bmatrix}\]
\[A = BX\]

\[ \Rightarrow B^{- 1} A = B^{- 1} BX\]

\[ \Rightarrow B^{- 1} A = IX\]

\[ \Rightarrow X = B^{- 1} A . . . \left( 1 \right)\]

Now,

\[B = \begin{bmatrix}1 & 0 \\ 0 & 2\end{bmatrix}\]

\[adjB = \begin{bmatrix}2 & 0 \\ 0 & 1\end{bmatrix}\]

\[\left| B \right| = 2\]

\[ \therefore B^{- 1} = \frac{1}{\left| B \right|}adjB = \frac{1}{2}\begin{bmatrix}2 & 0 \\ 0 & 1\end{bmatrix}\]

On putting the value of B-1 in eq. (1), we get

\[X = \frac{1}{2}\begin{bmatrix}2 & 0 \\ 0 & 1\end{bmatrix}\begin{bmatrix}1 & 2 \\ 3 & - 5\end{bmatrix}\]

\[ \Rightarrow X = \frac{1}{2}\begin{bmatrix}2 & 4 \\ 3 & - 5\end{bmatrix}\]

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Chapter 7: Adjoint and Inverse of a Matrix - Exercise 7.4 [Page 38]

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RD Sharma Mathematics [English] Class 12
Chapter 7 Adjoint and Inverse of a Matrix
Exercise 7.4 | Q 23 | Page 38

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