Question

Jayanti takes shortest route to her home by walking diagonally across a rectangular park. The park measures 60 metres × 80 metres. How much shorter is the route across the park than the route around its edges?

Answer 1

As the park is rectangular, all the angles area of 90°

In right angled ΔABC,

AC² = AB² + BC²  ...[By Pythagoras theorem]

⇒ AC² = (60)² + (80)² = 3600 + 6400

⇒ AC² = 10000

⇒ AC = `sqrt(10000)`

⇒ AC = 100 m

If she goes through AB and AC, then the total distance covered = (60 + 80) m = 140 m

∴ Difference between two paths = (140 – 100) m = 40 m.