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Question
Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place?
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Solution
Let A be the starting point and B be the ending point of Jiya.
Since ∆ABC is right-angled.
∴ (AB)2 = (AC)2 + (BC)2
⇒ (AB)2 = 62 + 82
= 36 + 64
= 100
⇒ AB = 10
Thus, Jiya is 10 km away from her starting place.
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