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Question
In ΔPQR of the given figure, PQ = PR. Find the measures of ∠Q and ∠R.

Sum
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Solution
∠PRQ = ∠PQR ...[∵ PQ = PR (Given)]
Now, in ∆PQR,
∠PQR + ∠PRQ + ∠QPR = 180° ...[Angle sum property]
⇒ 2∠PQR + 30° = 180° ...[Using (i)]
⇒ 2∠PQR = 180° – 30° = 150°
⇒ ∠PQR = `150^circ/2` = 75°
Thus, ∠Q = ∠R = 75°
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