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Integrate the function: 1cos(x+a)cos(x+b) - Mathematics

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Question

Integrate the function:

`1/(cos (x+a) cos(x+b))`

Sum
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Solution

Let I = `1/(cos (x + a) cos (x + b))  dx`

`= 1/(sin (a - b)) int (sin [(x + a) - (x + b)])/(cos (x + a) cos (x + b))`dx

`= 1/(sin (a + b)) int (sin (x + a) cos (x + b) - cos (x + a) sin (x + b))/(cos (x + a) cos (x + b))  dx`

`= 1/(sin (a - b)) int [(sin (x + a))/(cos (x + a)) - (sin (x + b))/(cos (x + b))]  dx`

`= 1/(sin (a - b)) int [tan (x + a) - tan (x + b)]  dx`

`= 1/(sin (a - b)) = [log |cos (x + a)| - log |cos (x + b)|] + C`

`= 1/(sin (a - b)) = [log |sec(x + a)| - log |sec(x + b)|] + C`

`= 1/(sin (a - b)) log |(sec(x + a))/(sec(x + b))| + C`

or `= 1/(sin (a - b)) log |(cos (x + a))/(cos (x + b))| + C`

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Chapter 7: Integrals - Exercise 7.12 [Page 352]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.12 | Q 11 | Page 352

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