Question

Which antiderivative has derivative \(1\)?

Options

• \[\frac{x^2}{2}+\mathrm{C}\]

• \[e^x+\mathrm{C}\]

• \[x+\mathrm{C}\]

• \[\log|x|+\mathrm{C}\]

Answer 1

Since \(\frac{d}{dx}(x)=1\), an antiderivative of \(1\) is \(x\). Thus, \(\int dx=x+\mathrm{C}\).