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Question
Which expression is also an antiderivative of \[\frac{1}{\sqrt{1-x^2}}\]?
Options
\[-\cos^{-1}x+\mathrm{C}\]
\[\cos^{-1}x+\mathrm{C}\]
\[-\sin^{-1}x+\mathrm{C}\]
\[\tan^{-1}x+\mathrm{C}\]
MCQ
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Solution
The derivative of \(-\cos^{-1}x\) is \(\frac{1}{\sqrt{1-x^2}}\). So \(-\cos^{-1}x+\mathrm{C}\) is also an antiderivative of this integrand.
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