मराठी

Which expression is also an antiderivative of \[\frac{1}{\sqrt{1-x^2}}\]?

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प्रश्न

Which expression is also an antiderivative of \[\frac{1}{\sqrt{1-x^2}}\]?

पर्याय

  • \[-\cos^{-1}x+\mathrm{C}\]

  • \[\cos^{-1}x+\mathrm{C}\]

  • \[-\sin^{-1}x+\mathrm{C}\]

  • \[\tan^{-1}x+\mathrm{C}\]

MCQ
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उत्तर

The derivative of \(-\cos^{-1}x\) is \(\frac{1}{\sqrt{1-x^2}}\). So \(-\cos^{-1}x+\mathrm{C}\) is also an antiderivative of this integrand.

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