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In NaOH solution [OH–] is 2.87 × 10–4. Calculate the pH of the solution.

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Question

In NaOH solution [OH] is 2.87 × 104. Calculate the pH of the solution.

Numerical
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Solution

Given: [OH] = `2.87 xx 10^-4` M

To find: pH of the solution

Formulae: 

i. pOH = –log10[OH]

ii. pH + pOH = 14

Calculation:

From formula (i),

pOH = –log10[OH]

∴ pOH = –log10[2.87 × 10–4]

= –log102.87 – log10104

∴ –log102.87 + 4 = 4 – 0.4579

pOH = 3.5421

From formula (ii),

pH + pOH = 14

pH = 14 – pOH

= 14 – 3.5421

= 10.4579

pH of the solution is 10.4579

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Chapter 3: Ionic Equilibria - Exercises [Page 62]

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