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Question
In NaOH solution [OH–] is 2.87 × 10–4. Calculate the pH of the solution.
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Solution
Given: [OH–] = `2.87 xx 10^-4` M
To find: pH of the solution
Formulae:
i. pOH = –log10[OH–]
ii. pH + pOH = 14
Calculation:
From formula (i),
pOH = –log10[OH–]
∴ pOH = –log10[2.87 × 10–4]
= –log102.87 – log1010–4
∴ –log102.87 + 4 = 4 – 0.4579
pOH = 3.5421
From formula (ii),
pH + pOH = 14
pH = 14 – pOH
= 14 – 3.5421
= 10.4579
pH of the solution is 10.4579
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