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Karnataka Board PUCPUC Science Class 11

Calculate the pH of the following solution: 0.3 g of NaOH dissolved in water to give 200 mL of solution.

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Question

Calculate the pH of the following solution:  

0.3 g of NaOH dissolved in water to give 200 mL of solution.

Numerical
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Solution

For 0.3 g of NaOH dissolved in water to give 200 mL of solution:

\[\ce{NaOH -> Na^+_{(aq)} + OH^-_{(aq)}}\]

`["NaOH"] = 0.3 xx 1000/200 = 1.5 "M"`

`["OH"_("aq")^-] = 1.5 "M"`

Then `["H"^+] = 10^(-14)/1.5`

`= 6.66 xx 10^(-13)`

`"pH" = - log(6.66  xx 10^(-13))`

=  12.18

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Chapter 6: Equilibrium - EXERCISES [Page 237]

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NCERT Chemistry Part 1 and 2 [English] Class 11
Chapter 6 Equilibrium
EXERCISES | Q 7.49 - c) | Page 237

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