Advertisements
Advertisements
Question
The pH of 10−5 M KOH solution will be ____________.
Options
9
5
19
none of these
Advertisements
Solution
The pH of 10−5 M KOH solution will be 9.
Explanation:
\[\ce{\underset{10^{-5} m}{KOH} -> \underset{10^{-5} m}{K^+} + \underset{10^{-5} m}{OH^-}}\]
[OH–] = 10−5 M
pH = 14 – pOH
pH = 14 – (– log [OH–])
= 14 + log [OH–]
= 14 + log 10−5
= 14 – 5
= 9
APPEARS IN
RELATED QUESTIONS
Assuming complete dissociation, calculate the pH of the following solution:
0.002 M KOH
Calculate the pH of the following solution:
0.3 g of NaOH dissolved in water to give 200 mL of solution.
The degree of ionization of a 0.1M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the pKa of bromoacetic acid.
Answer the following :
The pH of rainwater collected in a certain region of Maharashtra on a particular day was 5.1. Calculate the H+ ion concentration of the rainwater and its percent dissociation.
The least basic hydroxide from the following is:
In which of the following solvents is silver chloride most soluble?
The aqueous solution of sugar does not conduct electricity. However, when sodium chloride is added to water, it conducts electricity. How will you explain this statement on the basis of ionisation and how is it affected by concentration of sodium chloride?
The mole fraction of the solute molal aqueous solution is:
Define pOH.
Define pH.
